Base | Representation |
---|---|
bin | 1011110011010100111… |
… | …01110101111111011001 |
3 | 1102202200220111121010111 |
4 | 11321222131311333121 |
5 | 23120442330242131 |
6 | 510142401444321 |
7 | 41203664524051 |
oct | 5715235657731 |
9 | 1382626447114 |
10 | 405513134041 |
11 | 146a82657624 |
12 | 667116406a1 |
13 | 2c3168a0232 |
14 | 158ac478561 |
15 | a83590eab1 |
hex | 5e6a775fd9 |
405513134041 has 2 divisors, whose sum is σ = 405513134042. Its totient is φ = 405513134040.
The previous prime is 405513134003. The next prime is 405513134063. The reversal of 405513134041 is 140431315504.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 328897662016 + 76615472025 = 573496^2 + 276795^2 .
It is a cyclic number.
It is not a de Polignac number, because 405513134041 - 211 = 405513131993 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 405513133994 and 405513134012.
It is not a weakly prime, because it can be changed into another prime (405513131041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202756567020 + 202756567021.
It is an arithmetic number, because the mean of its divisors is an integer number (202756567021).
Almost surely, 2405513134041 is an apocalyptic number.
It is an amenable number.
405513134041 is a deficient number, since it is larger than the sum of its proper divisors (1).
405513134041 is an equidigital number, since it uses as much as digits as its factorization.
405513134041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 405513134041 its reverse (140431315504), we get a palindrome (545944449545).
The spelling of 405513134041 in words is "four hundred five billion, five hundred thirteen million, one hundred thirty-four thousand, forty-one".
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