Base | Representation |
---|---|
bin | 1011110100011111000… |
… | …11110001111000000001 |
3 | 1102211022021111101002010 |
4 | 11322033203301320001 |
5 | 23123231133301131 |
6 | 510324232043133 |
7 | 41225262224502 |
oct | 5721743617001 |
9 | 1384267441063 |
10 | 406135447041 |
11 | 147271965595 |
12 | 66865b334a9 |
13 | 2c3b57abc8c |
14 | 1592ad8cba9 |
15 | a870388b46 |
hex | 5e8f8f1e01 |
406135447041 has 4 divisors (see below), whose sum is σ = 541513929392. Its totient is φ = 270756964692.
The previous prime is 406135447009. The next prime is 406135447063. The reversal of 406135447041 is 140744531604.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 406135447041 - 25 = 406135447009 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (406135447241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67689241171 + ... + 67689241176.
It is an arithmetic number, because the mean of its divisors is an integer number (135378482348).
Almost surely, 2406135447041 is an apocalyptic number.
It is an amenable number.
406135447041 is a deficient number, since it is larger than the sum of its proper divisors (135378482351).
406135447041 is a wasteful number, since it uses less digits than its factorization.
406135447041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135378482350.
The product of its (nonzero) digits is 161280, while the sum is 39.
Adding to 406135447041 its reverse (140744531604), we get a palindrome (546879978645).
The spelling of 406135447041 in words is "four hundred six billion, one hundred thirty-five million, four hundred forty-seven thousand, forty-one".
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