Base | Representation |
---|---|
bin | 10010011110000010010110… |
… | …00001011000101011101001 |
3 | 12022210201001012112000120001 |
4 | 21033001023001120223221 |
5 | 20310411413131433132 |
6 | 222214010224103001 |
7 | 11361204261601135 |
oct | 1117011301305351 |
9 | 168721035460501 |
10 | 40614469405417 |
11 | 11a39555187066 |
12 | 467b433764a61 |
13 | 1987c0ab6640b |
14 | a05a723063c5 |
15 | 4a671eee0ce7 |
hex | 24f04b058ae9 |
40614469405417 has 2 divisors, whose sum is σ = 40614469405418. Its totient is φ = 40614469405416.
The previous prime is 40614469405337. The next prime is 40614469405567. The reversal of 40614469405417 is 71450496441604.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33062833500841 + 7551635904576 = 5750029^2 + 2748024^2 .
It is a cyclic number.
It is not a de Polignac number, because 40614469405417 - 211 = 40614469403369 is a prime.
It is not a weakly prime, because it can be changed into another prime (40614469405817) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20307234702708 + 20307234702709.
It is an arithmetic number, because the mean of its divisors is an integer number (20307234702709).
Almost surely, 240614469405417 is an apocalyptic number.
It is an amenable number.
40614469405417 is a deficient number, since it is larger than the sum of its proper divisors (1).
40614469405417 is an equidigital number, since it uses as much as digits as its factorization.
40614469405417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11612160, while the sum is 55.
The spelling of 40614469405417 in words is "forty trillion, six hundred fourteen billion, four hundred sixty-nine million, four hundred five thousand, four hundred seventeen".
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