4062410142113 has 4 divisors (see below), whose sum is σ = 4104290659140. Its totient is φ = 4020529625088.

The previous prime is 4062410142059. The next prime is 4062410142169. The reversal of 4062410142113 is 3112410142604.

4062410142113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1496541182224 + 2565868959889 = 1223332^2 + 1601833^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4062410142113 is a prime.

It is a super-2 number, since 2×4062410142113² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (4062410112113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20940258368 + ... + 20940258561.

It is an arithmetic number, because the mean of its divisors is an integer number (1026072664785).

Almost surely, 2^{4062410142113} is an apocalyptic number.

It is an amenable number.

4062410142113 is a deficient number, since it is larger than the sum of its proper divisors (41880517027).

4062410142113 is an equidigital number, since it uses as much as digits as its factorization.

4062410142113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 41880517026.

The product of its (nonzero) digits is 4608, while the sum is 29.

Adding to 4062410142113 its reverse (3112410142604), we get a palindrome (7174820284717).

The spelling of 4062410142113 in words is "four trillion, sixty-two billion, four hundred ten million, one hundred forty-two thousand, one hundred thirteen".