Base | Representation |
---|---|
bin | 111011001000100110011… |
… | …010010000011001001001 |
3 | 112101111002002101122002201 |
4 | 323020212122100121021 |
5 | 1013034410432312423 |
6 | 12350455212000201 |
7 | 566406602436016 |
oct | 73104632203111 |
9 | 15344062348081 |
10 | 4063683479113 |
11 | 1327442425045 |
12 | 55769b460061 |
13 | 23628571385b |
14 | 10097d0b270d |
15 | 70a8bcae2ad |
hex | 3b226690649 |
4063683479113 has 2 divisors, whose sum is σ = 4063683479114. Its totient is φ = 4063683479112.
The previous prime is 4063683478951. The next prime is 4063683479129. The reversal of 4063683479113 is 3119743863604.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2386119715849 + 1677563763264 = 1544707^2 + 1295208^2 .
It is a cyclic number.
It is not a de Polignac number, because 4063683479113 - 225 = 4063649924681 is a prime.
It is not a weakly prime, because it can be changed into another prime (4063683479173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2031841739556 + 2031841739557.
It is an arithmetic number, because the mean of its divisors is an integer number (2031841739557).
Almost surely, 24063683479113 is an apocalyptic number.
It is an amenable number.
4063683479113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4063683479113 is an equidigital number, since it uses as much as digits as its factorization.
4063683479113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7838208, while the sum is 55.
The spelling of 4063683479113 in words is "four trillion, sixty-three billion, six hundred eighty-three million, four hundred seventy-nine thousand, one hundred thirteen".
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