Base | Representation |
---|---|
bin | 101110001110000111110111… |
… | …0110010010000101011111001 |
3 | 1222022111212211002210200220212 |
4 | 1130130033232302100223321 |
5 | 411242100033222100032 |
6 | 4000403405003400505 |
7 | 151431041254554224 |
oct | 13434175662205371 |
9 | 1868455732720825 |
10 | 406561315425017 |
11 | 1085a775a586915 |
12 | 39722381b23135 |
13 | 145b174bb6169c |
14 | 725795bac85bb |
15 | 32008d5b87bb2 |
hex | 171c3eec90af9 |
406561315425017 has 2 divisors, whose sum is σ = 406561315425018. Its totient is φ = 406561315425016.
The previous prime is 406561315424977. The next prime is 406561315425037. The reversal of 406561315425017 is 710524513165604.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 356464066625536 + 50097248799481 = 18880256^2 + 7077941^2 .
It is a cyclic number.
It is not a de Polignac number, because 406561315425017 - 222 = 406561311230713 is a prime.
It is not a weakly prime, because it can be changed into another prime (406561315425037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 203280657712508 + 203280657712509.
It is an arithmetic number, because the mean of its divisors is an integer number (203280657712509).
Almost surely, 2406561315425017 is an apocalyptic number.
It is an amenable number.
406561315425017 is a deficient number, since it is larger than the sum of its proper divisors (1).
406561315425017 is an equidigital number, since it uses as much as digits as its factorization.
406561315425017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024000, while the sum is 50.
The spelling of 406561315425017 in words is "four hundred six trillion, five hundred sixty-one billion, three hundred fifteen million, four hundred twenty-five thousand, seventeen".
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