Base | Representation |
---|---|
bin | 111011001110100100111… |
… | …100111011111111101001 |
3 | 112102002122100222012111222 |
4 | 323032210330323333221 |
5 | 1013141031433421423 |
6 | 12353440115431425 |
7 | 600024623435213 |
oct | 73164474737751 |
9 | 15362570865458 |
10 | 4070101467113 |
11 | 132a136197460 |
12 | 5589908b5575 |
13 | 236a6927b5a6 |
14 | 100dcb6095b3 |
15 | 70d154603c8 |
hex | 3b3a4f3bfe9 |
4070101467113 has 16 divisors (see below), whose sum is σ = 4571242596096. Its totient is φ = 3591871471440.
The previous prime is 4070101467071. The next prime is 4070101467149. The reversal of 4070101467113 is 3117641010704.
It is a cyclic number.
It is not a de Polignac number, because 4070101467113 - 212 = 4070101463017 is a prime.
It is not an unprimeable number, because it can be changed into a prime (4070101467163) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 26318195 + ... + 26472392.
It is an arithmetic number, because the mean of its divisors is an integer number (285702662256).
Almost surely, 24070101467113 is an apocalyptic number.
4070101467113 is a gapful number since it is divisible by the number (43) formed by its first and last digit.
It is an amenable number.
4070101467113 is a deficient number, since it is larger than the sum of its proper divisors (501141128983).
4070101467113 is a wasteful number, since it uses less digits than its factorization.
4070101467113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52790804.
The product of its (nonzero) digits is 14112, while the sum is 35.
Adding to 4070101467113 its reverse (3117641010704), we get a palindrome (7187742477817).
The spelling of 4070101467113 in words is "four trillion, seventy billion, one hundred one million, four hundred sixty-seven thousand, one hundred thirteen".
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