Base | Representation |
---|---|
bin | 1001101101111… |
… | …0000011101001 |
3 | 2211200120221111 |
4 | 2123132003221 |
5 | 40413133213 |
6 | 4013310321 |
7 | 1003262335 |
oct | 233360351 |
9 | 84616844 |
10 | 40755433 |
11 | 21007184 |
12 | 117953a1 |
13 | 859c654 |
14 | 55ac7c5 |
15 | 38a0a3d |
hex | 26de0e9 |
40755433 has 2 divisors, whose sum is σ = 40755434. Its totient is φ = 40755432.
The previous prime is 40755401. The next prime is 40755461. The reversal of 40755433 is 33455704.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 40297104 + 458329 = 6348^2 + 677^2 .
It is a cyclic number.
It is not a de Polignac number, because 40755433 - 25 = 40755401 is a prime.
It is a super-2 number, since 2×407554332 = 3322010638034978, which contains 22 as substring.
It is equal to p2476831 and since 40755433 and 2476831 have the same sum of digits, it is a Honaker prime.
It is a junction number, because it is equal to n+sod(n) for n = 40755395 and 40755404.
It is not a weakly prime, because it can be changed into another prime (40755233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20377716 + 20377717.
It is an arithmetic number, because the mean of its divisors is an integer number (20377717).
Almost surely, 240755433 is an apocalyptic number.
It is an amenable number.
40755433 is a deficient number, since it is larger than the sum of its proper divisors (1).
40755433 is an equidigital number, since it uses as much as digits as its factorization.
40755433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 31.
The square root of 40755433 is about 6383.9981986213. The cubic root of 40755433 is about 344.1347301032.
The spelling of 40755433 in words is "forty million, seven hundred fifty-five thousand, four hundred thirty-three".
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