Base | Representation |
---|---|
bin | 10010100100011110000111… |
… | …10000000010111100001011 |
3 | 12100120211122212112011001111 |
4 | 21102033003300002330023 |
5 | 20323022140242011042 |
6 | 222503330504231151 |
7 | 11413161463623535 |
oct | 1122170360027413 |
9 | 170524585464044 |
10 | 40835538235147 |
11 | 12014288831937 |
12 | 46b624b16b4b7 |
13 | 19a2a0c119336 |
14 | a12644616855 |
15 | 4ac35ce5b517 |
hex | 2523c3c02f0b |
40835538235147 has 2 divisors, whose sum is σ = 40835538235148. Its totient is φ = 40835538235146.
The previous prime is 40835538235111. The next prime is 40835538235153. The reversal of 40835538235147 is 74153283553804.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40835538235147 - 211 = 40835538233099 is a prime.
It is a super-2 number, since 2×408355382351472 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 40835538235091 and 40835538235100.
It is not a weakly prime, because it can be changed into another prime (40835538239147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20417769117573 + 20417769117574.
It is an arithmetic number, because the mean of its divisors is an integer number (20417769117574).
Almost surely, 240835538235147 is an apocalyptic number.
40835538235147 is a deficient number, since it is larger than the sum of its proper divisors (1).
40835538235147 is an equidigital number, since it uses as much as digits as its factorization.
40835538235147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48384000, while the sum is 58.
The spelling of 40835538235147 in words is "forty trillion, eight hundred thirty-five billion, five hundred thirty-eight million, two hundred thirty-five thousand, one hundred forty-seven".
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