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409161339953 is a prime number
BaseRepresentation
bin1011111010000111110…
…10101001010000110001
31110010010011020122210222
411331003322221100301
523200430300334303
6511544403302425
741363254001642
oct5750372512061
91403104218728
10409161339953
11148584a00733
126736b37aa15
132c77865ac62
1415b36bb56c9
15a99ad44938
hex5f43ea9431

409161339953 has 2 divisors, whose sum is σ = 409161339954. Its totient is φ = 409161339952.

The previous prime is 409161339947. The next prime is 409161340001. The reversal of 409161339953 is 359933161904.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 277484525824 + 131676814129 = 526768^2 + 362873^2 .

It is a cyclic number.

It is not a de Polignac number, because 409161339953 - 224 = 409144562737 is a prime.

It is a super-2 number, since 2×4091613399532 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 409161339895 and 409161339904.

It is not a weakly prime, because it can be changed into another prime (409161332953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 204580669976 + 204580669977.

It is an arithmetic number, because the mean of its divisors is an integer number (204580669977).

Almost surely, 2409161339953 is an apocalyptic number.

It is an amenable number.

409161339953 is a deficient number, since it is larger than the sum of its proper divisors (1).

409161339953 is an equidigital number, since it uses as much as digits as its factorization.

409161339953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2361960, while the sum is 53.

The spelling of 409161339953 in words is "four hundred nine billion, one hundred sixty-one million, three hundred thirty-nine thousand, nine hundred fifty-three".