Base | Representation |
---|---|
bin | 111011100101010010010… |
… | …101011100001101111011 |
3 | 112111102120201020102202101 |
4 | 323211102111130031323 |
5 | 1014041001201413103 |
6 | 12412551443244231 |
7 | 601550105556004 |
oct | 73452225341573 |
9 | 15442521212671 |
10 | 4094485185403 |
11 | 1339509164958 |
12 | 561656979677 |
13 | 239153c08372 |
14 | 102261bac1ab |
15 | 71790e9aa1d |
hex | 3b95255c37b |
4094485185403 has 2 divisors, whose sum is σ = 4094485185404. Its totient is φ = 4094485185402.
The previous prime is 4094485185383. The next prime is 4094485185419. The reversal of 4094485185403 is 3045815844904.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4094485185403 is a prime.
It is not a weakly prime, because it can be changed into another prime (4094485185443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2047242592701 + 2047242592702.
It is an arithmetic number, because the mean of its divisors is an integer number (2047242592702).
Almost surely, 24094485185403 is an apocalyptic number.
4094485185403 is a deficient number, since it is larger than the sum of its proper divisors (1).
4094485185403 is an equidigital number, since it uses as much as digits as its factorization.
4094485185403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11059200, while the sum is 55.
The spelling of 4094485185403 in words is "four trillion, ninety-four billion, four hundred eighty-five million, one hundred eighty-five thousand, four hundred three".
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