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41001201841 is a prime number
BaseRepresentation
bin100110001011110111…
…001011000010110001
310220211102222212020011
4212023313023002301
51132432301424331
630500302014521
72651022315415
oct461367130261
9126742885204
1041001201841
1116430122886
127b43277441
133b356207a2
141dad54cd45
1510ee8543b1
hex98bdcb0b1

41001201841 has 2 divisors, whose sum is σ = 41001201842. Its totient is φ = 41001201840.

The previous prime is 41001201823. The next prime is 41001201883. The reversal of 41001201841 is 14810210014.

41001201841 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35715330225 + 5285871616 = 188985^2 + 72704^2 .

It is a cyclic number.

It is not a de Polignac number, because 41001201841 - 25 = 41001201809 is a prime.

It is not a weakly prime, because it can be changed into another prime (41001201811) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20500600920 + 20500600921.

It is an arithmetic number, because the mean of its divisors is an integer number (20500600921).

Almost surely, 241001201841 is an apocalyptic number.

It is an amenable number.

41001201841 is a deficient number, since it is larger than the sum of its proper divisors (1).

41001201841 is an equidigital number, since it uses as much as digits as its factorization.

41001201841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 22.

Adding to 41001201841 its reverse (14810210014), we get a palindrome (55811411855).

The spelling of 41001201841 in words is "forty-one billion, one million, two hundred one thousand, eight hundred forty-one".