Search a number
-
+
41001624806713 is a prime number
BaseRepresentation
bin10010101001010011011110…
…10010000010010100111001
312101011201100201201011120221
421110221233102002110321
520333232311422303323
6223111515244020041
711431161325321414
oct1124515722022471
9171151321634527
1041001624806713
111207876732532a
124722481231621
1319b558a37329c
14a1a6bc632b7b
154b182de3255d
hex254a6f482539

41001624806713 has 2 divisors, whose sum is σ = 41001624806714. Its totient is φ = 41001624806712.

The previous prime is 41001624806687. The next prime is 41001624806789. The reversal of 41001624806713 is 31760842610014.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40795646799609 + 205978007104 = 6387147^2 + 453848^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41001624806713 is a prime.

It is a super-2 number, since 2×410016248067132 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 41001624806713.

It is not a weakly prime, because it can be changed into another prime (41001624806413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20500812403356 + 20500812403357.

It is an arithmetic number, because the mean of its divisors is an integer number (20500812403357).

Almost surely, 241001624806713 is an apocalyptic number.

It is an amenable number.

41001624806713 is a deficient number, since it is larger than the sum of its proper divisors (1).

41001624806713 is an equidigital number, since it uses as much as digits as its factorization.

41001624806713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 193536, while the sum is 43.

The spelling of 41001624806713 in words is "forty-one trillion, one billion, six hundred twenty-four million, eight hundred six thousand, seven hundred thirteen".