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41004094262713 is a prime number
BaseRepresentation
bin10010101001011000000100…
…11110010000110110111001
312101011221201211102112101021
421110230002132100312321
520333302341112401323
6223113004301022441
711431306452334531
oct1124540236206671
9171157654375337
1041004094262713
111207981426715a
124722a50254a21
1319b5891b69c5a
14a1a8745b24c1
154b1925b2805d
hex254b02790db9

41004094262713 has 2 divisors, whose sum is σ = 41004094262714. Its totient is φ = 41004094262712.

The previous prime is 41004094262687. The next prime is 41004094262777. The reversal of 41004094262713 is 31726249040014.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 39054462913449 + 1949631349264 = 6249357^2 + 1396292^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41004094262713 is a prime.

It is a super-3 number, since 3×410040942627133 (a number of 42 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 41004094262713.

It is not a weakly prime, because it can be changed into another prime (41004094266713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20502047131356 + 20502047131357.

It is an arithmetic number, because the mean of its divisors is an integer number (20502047131357).

Almost surely, 241004094262713 is an apocalyptic number.

It is an amenable number.

41004094262713 is a deficient number, since it is larger than the sum of its proper divisors (1).

41004094262713 is an equidigital number, since it uses as much as digits as its factorization.

41004094262713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 290304, while the sum is 43.

The spelling of 41004094262713 in words is "forty-one trillion, four billion, ninety-four million, two hundred sixty-two thousand, seven hundred thirteen".