Base | Representation |
---|---|
bin | 10010101001011000000110… |
… | …11110010000111000011011 |
3 | 12101011221202222222220112021 |
4 | 21110230003132100320123 |
5 | 20333302404411240102 |
6 | 223113010100355311 |
7 | 11431310045052142 |
oct | 1124540336207033 |
9 | 171157688886467 |
10 | 41004111040027 |
11 | 12079822786203 |
12 | 4722a559a5b37 |
13 | 19b5895492565 |
14 | a1a8768dc759 |
15 | 4b192733e137 |
hex | 254b03790e1b |
41004111040027 has 2 divisors, whose sum is σ = 41004111040028. Its totient is φ = 41004111040026.
The previous prime is 41004111039959. The next prime is 41004111040033. The reversal of 41004111040027 is 72004011140014.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41004111040027 is a prime.
It is a super-3 number, since 3×410041110400273 (a number of 42 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41004111039983 and 41004111040010.
It is not a weakly prime, because it can be changed into another prime (41004111040727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20502055520013 + 20502055520014.
It is an arithmetic number, because the mean of its divisors is an integer number (20502055520014).
Almost surely, 241004111040027 is an apocalyptic number.
41004111040027 is a deficient number, since it is larger than the sum of its proper divisors (1).
41004111040027 is an equidigital number, since it uses as much as digits as its factorization.
41004111040027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 25.
The spelling of 41004111040027 in words is "forty-one trillion, four billion, one hundred eleven million, forty thousand, twenty-seven".
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