4102240312433 has 4 divisors (see below), whose sum is σ = 4102354543728. Its totient is φ = 4102126081140.

The previous prime is 4102240312411. The next prime is 4102240312481. The reversal of 4102240312433 is 3342130422014.

4102240312433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4102240312433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4102240312396 and 4102240312405.

It is not an unprimeable number, because it can be changed into a prime (4102240312483) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57061763 + ... + 57133608.

It is an arithmetic number, because the mean of its divisors is an integer number (1025588635932).

Almost surely, 2^{4102240312433} is an apocalyptic number.

It is an amenable number.

4102240312433 is a deficient number, since it is larger than the sum of its proper divisors (114231295).

4102240312433 is a wasteful number, since it uses less digits than its factorization.

4102240312433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114231294.

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 4102240312433 its reverse (3342130422014), we get a palindrome (7444370734447).

The spelling of 4102240312433 in words is "four trillion, one hundred two billion, two hundred forty million, three hundred twelve thousand, four hundred thirty-three".