Base | Representation |
---|---|
bin | 10010101001111101110010… |
… | …10001011100001111000011 |
3 | 12101020212222212020102010211 |
4 | 21110332321101130033003 |
5 | 20334120322244014110 |
6 | 223130153322534551 |
7 | 11432624261640511 |
oct | 1124767121341703 |
9 | 171225885212124 |
10 | 41024341001155 |
11 | 12087363aa1446 |
12 | 4726960967457 |
13 | 19b776a6b4865 |
14 | a1b8355654b1 |
15 | 4b220d38198a |
hex | 254fb945c3c3 |
41024341001155 has 16 divisors (see below), whose sum is σ = 50445116769600. Its totient is φ = 32009350141440.
The previous prime is 41024341001117. The next prime is 41024341001159. The reversal of 41024341001155 is 55110014342014.
It is not a de Polignac number, because 41024341001155 - 225 = 41024307446723 is a prime.
It is a super-2 number, since 2×410243410011552 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (41024341001159) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29467050 + ... + 30827839.
It is an arithmetic number, because the mean of its divisors is an integer number (3152819798100).
Almost surely, 241024341001155 is an apocalyptic number.
41024341001155 is a deficient number, since it is larger than the sum of its proper divisors (9420775768445).
41024341001155 is a wasteful number, since it uses less digits than its factorization.
41024341001155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60298254.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 41024341001155 its reverse (55110014342014), we get a palindrome (96134355343169).
The spelling of 41024341001155 in words is "forty-one trillion, twenty-four billion, three hundred forty-one million, one thousand, one hundred fifty-five".
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