Base | Representation |
---|---|
bin | 111011101101011010100… |
… | …011111101010010100001 |
3 | 112112021002222102122000121 |
4 | 323231122203331102201 |
5 | 1014211340031040301 |
6 | 12420553505520241 |
7 | 602306306152054 |
oct | 73553243752241 |
9 | 15467088378017 |
10 | 4103213143201 |
11 | 1342187937817 |
12 | 563291943081 |
13 | 239c151c9133 |
14 | 10284d00aa9b |
15 | 71b0233c3a1 |
hex | 3bb5a8fd4a1 |
4103213143201 has 2 divisors, whose sum is σ = 4103213143202. Its totient is φ = 4103213143200.
The previous prime is 4103213143171. The next prime is 4103213143217. The reversal of 4103213143201 is 1023413123014.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3623982312976 + 479230830225 = 1903676^2 + 692265^2 .
It is a cyclic number.
It is not a de Polignac number, because 4103213143201 - 213 = 4103213135009 is a prime.
It is not a weakly prime, because it can be changed into another prime (4103213143301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2051606571600 + 2051606571601.
It is an arithmetic number, because the mean of its divisors is an integer number (2051606571601).
Almost surely, 24103213143201 is an apocalyptic number.
It is an amenable number.
4103213143201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4103213143201 is an equidigital number, since it uses as much as digits as its factorization.
4103213143201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4103213143201 its reverse (1023413123014), we get a palindrome (5126626266215).
The spelling of 4103213143201 in words is "four trillion, one hundred three billion, two hundred thirteen million, one hundred forty-three thousand, two hundred one".
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