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4104013130011 = 7015854512311
BaseRepresentation
bin111011101110001010001…
…111101010100100011011
3112112100011201202011121201
4323232022033222210123
51014220004330130021
612421205124215031
7602335162012114
oct73561217524433
915470151664551
104104013130011
111342558469743
1256347583a477
1323a011b76002
141028c737120b
1571b4c6b0591
hex3bb8a3ea91b

4104013130011 has 4 divisors (see below), whose sum is σ = 4109867643024. Its totient is φ = 4098158617000.

The previous prime is 4104013129991. The next prime is 4104013130033. The reversal of 4104013130011 is 1100313104014.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4104013130011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (4104013130081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2927255455 + ... + 2927256856.

It is an arithmetic number, because the mean of its divisors is an integer number (1027466910756).

Almost surely, 24104013130011 is an apocalyptic number.

4104013130011 is a deficient number, since it is larger than the sum of its proper divisors (5854513013).

4104013130011 is an equidigital number, since it uses as much as digits as its factorization.

4104013130011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5854513012.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 4104013130011 its reverse (1100313104014), we get a palindrome (5204326234025).

The spelling of 4104013130011 in words is "four trillion, one hundred four billion, thirteen million, one hundred thirty thousand, eleven".

Divisors: 1 701 5854512311 4104013130011