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41041312153 is a prime number
BaseRepresentation
bin100110001110010000…
…001011100110011001
310220221020110200020021
4212032100023212121
51133023033442103
630504253430441
72652020253202
oct461620134631
9126836420207
1041041312153
11164508292a6
127b5479b421
133b40a255ba
141db49d05a9
151103128bbd
hex98e40b999

41041312153 has 2 divisors, whose sum is σ = 41041312154. Its totient is φ = 41041312152.

The previous prime is 41041312097. The next prime is 41041312177. The reversal of 41041312153 is 35121314014.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32476364944 + 8564947209 = 180212^2 + 92547^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41041312153 is a prime.

It is not a weakly prime, because it can be changed into another prime (41041312853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20520656076 + 20520656077.

It is an arithmetic number, because the mean of its divisors is an integer number (20520656077).

Almost surely, 241041312153 is an apocalyptic number.

It is an amenable number.

41041312153 is a deficient number, since it is larger than the sum of its proper divisors (1).

41041312153 is an equidigital number, since it uses as much as digits as its factorization.

41041312153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 41041312153 its reverse (35121314014), we get a palindrome (76162626167).

The spelling of 41041312153 in words is "forty-one billion, forty-one million, three hundred twelve thousand, one hundred fifty-three".