Base | Representation |
---|---|
bin | 111011101110101010011… |
… | …011100101000011000001 |
3 | 112112101120100211201011022 |
4 | 323232222123211003001 |
5 | 1014222111044432113 |
6 | 12421334454155225 |
7 | 602354436620525 |
oct | 73565233450301 |
9 | 15471510751138 |
10 | 4104553124033 |
11 | 134280526219a |
12 | 5635a6652b15 |
13 | 23a0999c1cbb |
14 | 102938d77d85 |
15 | 71b7ecc8908 |
hex | 3bbaa6e50c1 |
4104553124033 has 2 divisors, whose sum is σ = 4104553124034. Its totient is φ = 4104553124032.
The previous prime is 4104553123969. The next prime is 4104553124039. The reversal of 4104553124033 is 3304213554014.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3994609817104 + 109943306929 = 1998652^2 + 331577^2 .
It is a cyclic number.
It is not a de Polignac number, because 4104553124033 - 26 = 4104553123969 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4104553123984 and 4104553124002.
It is not a weakly prime, because it can be changed into another prime (4104553124039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2052276562016 + 2052276562017.
It is an arithmetic number, because the mean of its divisors is an integer number (2052276562017).
Almost surely, 24104553124033 is an apocalyptic number.
It is an amenable number.
4104553124033 is a deficient number, since it is larger than the sum of its proper divisors (1).
4104553124033 is an equidigital number, since it uses as much as digits as its factorization.
4104553124033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 4104553124033 its reverse (3304213554014), we get a palindrome (7408766678047).
The spelling of 4104553124033 in words is "four trillion, one hundred four billion, five hundred fifty-three million, one hundred twenty-four thousand, thirty-three".
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