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410979912193 is a prime number
BaseRepresentation
bin1011111101100000100…
…11111100101000000001
31110021210220012200221101
411332300103330220001
523213141324142233
6512445045454401
741456315420554
oct5766023745001
91407726180841
10410979912193
1114932849a9a4
1267798411401
132c9a83515c6
1415c6a52469b
15aa5581ac7d
hex5fb04fca01

410979912193 has 2 divisors, whose sum is σ = 410979912194. Its totient is φ = 410979912192.

The previous prime is 410979912127. The next prime is 410979912253. The reversal of 410979912193 is 391219979014.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 372309869584 + 38670042609 = 610172^2 + 196647^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-410979912193 is a prime.

It is not a weakly prime, because it can be changed into another prime (410979910193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205489956096 + 205489956097.

It is an arithmetic number, because the mean of its divisors is an integer number (205489956097).

Almost surely, 2410979912193 is an apocalyptic number.

It is an amenable number.

410979912193 is a deficient number, since it is larger than the sum of its proper divisors (1).

410979912193 is an equidigital number, since it uses as much as digits as its factorization.

410979912193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1102248, while the sum is 55.

The spelling of 410979912193 in words is "four hundred ten billion, nine hundred seventy-nine million, nine hundred twelve thousand, one hundred ninety-three".