41100143131 has 2 divisors, whose sum is σ = 41100143132. Its totient is φ = 41100143130.

The previous prime is 41100143099. The next prime is 41100143141. The reversal of 41100143131 is 13134100114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 41100143131 - 2⁵ = 41100143099 is a prime.

It is a super-2 number, since 2×41100143131² (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 41100143099 and 41100143108.

It is not a weakly prime, because it can be changed into another prime (41100143141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20550071565 + 20550071566.

It is an arithmetic number, because the mean of its divisors is an integer number (20550071566).

Almost surely, 2^41100143131 is an apocalyptic number.

41100143131 is a deficient number, since it is larger than the sum of its proper divisors (1).

41100143131 is an equidigital number, since it uses as much as digits as its factorization.

41100143131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 41100143131 its reverse (13134100114), we get a palindrome (54234243245).

The spelling of 41100143131 in words is "forty-one billion, one hundred million, one hundred forty-three thousand, one hundred thirty-one".