Base | Representation |
---|---|
bin | 10010101100001101001000… |
… | …11001100110110000101011 |
3 | 12101112020122021121100221202 |
4 | 21112012210121212300223 |
5 | 20341400430324344321 |
6 | 223225402054154415 |
7 | 11441320351413563 |
oct | 1126064431466053 |
9 | 171466567540852 |
10 | 41101300231211 |
11 | 12106a66521010 |
12 | 473985a352a0b |
13 | 19c1ab385bccc |
14 | a21456523da3 |
15 | 4b421490670b |
hex | 2561a4666c2b |
41101300231211 has 16 divisors (see below), whose sum is σ = 45224491536000. Its totient is φ = 37043821795200.
The previous prime is 41101300231177. The next prime is 41101300231217. The reversal of 41101300231211 is 11213200310114.
It is a de Polignac number, because none of the positive numbers 2k-41101300231211 is a prime.
It is a super-2 number, since 2×411013002312112 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41101300231217) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30880286 + ... + 32183763.
It is an arithmetic number, because the mean of its divisors is an integer number (2826530721000).
Almost surely, 241101300231211 is an apocalyptic number.
41101300231211 is a deficient number, since it is larger than the sum of its proper divisors (4123191304789).
41101300231211 is a wasteful number, since it uses less digits than its factorization.
41101300231211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63064570.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 41101300231211 its reverse (11213200310114), we get a palindrome (52314500541325).
The spelling of 41101300231211 in words is "forty-one trillion, one hundred one billion, three hundred million, two hundred thirty-one thousand, two hundred eleven".
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