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41101314121 = 721979558829
BaseRepresentation
bin100110010001110101…
…000100100001001001
310221002102101002110101
4212101311010201021
51133133414022441
630514235445401
72653346256100
oct462165044111
9127072332411
1041101314121
11164816906aa
127b708b6861
133b502a341a
141dbc96d037
15110852c231
hex991d44849

41101314121 has 24 divisors (see below), whose sum is σ = 50965296000. Its totient is φ = 32952969504.

The previous prime is 41101314113. The next prime is 41101314131. The reversal of 41101314121 is 12141310114.

It is not a de Polignac number, because 41101314121 - 23 = 41101314113 is a prime.

It is a super-2 number, since 2×411013141212 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19).

It is not an unprimeable number, because it can be changed into a prime (41101314131) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 205866 + ... + 352963.

It is an arithmetic number, because the mean of its divisors is an integer number (2123554000).

Almost surely, 241101314121 is an apocalyptic number.

It is an amenable number.

41101314121 is a deficient number, since it is larger than the sum of its proper divisors (9863981879).

41101314121 is a wasteful number, since it uses less digits than its factorization.

41101314121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 558941 (or 558934 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 41101314121 its reverse (12141310114), we get a palindrome (53242624235).

The spelling of 41101314121 in words is "forty-one billion, one hundred one million, three hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 7 19 49 79 133 553 931 1501 3871 10507 73549 558829 3911803 10617751 27382621 44147491 74324257 309032437 520269799 838802329 2163227059 5871616303 41101314121