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41101430313 = 313700476771
BaseRepresentation
bin100110010001110101…
…100000111000101001
310221002102120222211210
4212101311200320221
51133133431232223
630514242143333
72653350251616
oct462165407051
9127072528753
1041101430313
111648175aa29
127b70951b49
133b50314288
141dbc99d50d
151108551893
hex991d60e29

41101430313 has 4 divisors (see below), whose sum is σ = 54801907088. Its totient is φ = 27400953540.

The previous prime is 41101430311. The next prime is 41101430317. The reversal of 41101430313 is 31303410114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 41101430313 - 21 = 41101430311 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 41101430313.

It is not an unprimeable number, because it can be changed into a prime (41101430311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6850238383 + ... + 6850238388.

It is an arithmetic number, because the mean of its divisors is an integer number (13700476772).

Almost surely, 241101430313 is an apocalyptic number.

It is an amenable number.

41101430313 is a deficient number, since it is larger than the sum of its proper divisors (13700476775).

41101430313 is a wasteful number, since it uses less digits than its factorization.

41101430313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13700476774.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 41101430313 its reverse (31303410114), we get a palindrome (72404840427).

The spelling of 41101430313 in words is "forty-one billion, one hundred one million, four hundred thirty thousand, three hundred thirteen".

Divisors: 1 3 13700476771 41101430313