Base | Representation |
---|---|
bin | 10010101100010000100010… |
… | …11110011000111110110010 |
3 | 12101112102100211000111222220 |
4 | 21112020101132120332302 |
5 | 20341413202312431114 |
6 | 223230303424541510 |
7 | 11441413612045515 |
oct | 1126102136307662 |
9 | 171472324014886 |
10 | 41103130202034 |
11 | 1210781549619a |
12 | 473a08b181896 |
13 | 19c2015a13994 |
14 | a2158b59cd7c |
15 | 4b42c03d00a9 |
hex | 256211798fb2 |
41103130202034 has 32 divisors (see below), whose sum is σ = 82370496433344. Its totient is φ = 13673697220800.
The previous prime is 41103130202023. The next prime is 41103130202041. The reversal of 41103130202034 is 43020203130114.
It is a happy number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 41103130201995 and 41103130202013.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2897709 + ... + 9518559.
It is an arithmetic number, because the mean of its divisors is an integer number (2574078013542).
Almost surely, 241103130202034 is an apocalyptic number.
41103130202034 is an abundant number, since it is smaller than the sum of its proper divisors (41267366231310).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
41103130202034 is a wasteful number, since it uses less digits than its factorization.
41103130202034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6622922.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 41103130202034 its reverse (43020203130114), we get a palindrome (84123333332148).
The spelling of 41103130202034 in words is "forty-one trillion, one hundred three billion, one hundred thirty million, two hundred two thousand, thirty-four".
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