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41104123513 is a prime number
BaseRepresentation
bin100110010001111111…
…110010011001111001
310221002121122211012221
4212101333302121321
51133140123423023
630514420004041
72653412166535
oct462177623171
9127077584187
1041104123513
111648322a412
127b71830621
133b50a4809b
141dbd0a0bc5
1511088d485d
hex991ff2679

41104123513 has 2 divisors, whose sum is σ = 41104123514. Its totient is φ = 41104123512.

The previous prime is 41104123381. The next prime is 41104123609. The reversal of 41104123513 is 31532140114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36217134864 + 4886988649 = 190308^2 + 69907^2 .

It is a cyclic number.

It is not a de Polignac number, because 41104123513 - 29 = 41104123001 is a prime.

It is a super-2 number, since 2×411041235132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41104124513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20552061756 + 20552061757.

It is an arithmetic number, because the mean of its divisors is an integer number (20552061757).

Almost surely, 241104123513 is an apocalyptic number.

It is an amenable number.

41104123513 is a deficient number, since it is larger than the sum of its proper divisors (1).

41104123513 is an equidigital number, since it uses as much as digits as its factorization.

41104123513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 41104123513 its reverse (31532140114), we get a palindrome (72636263627).

The spelling of 41104123513 in words is "forty-one billion, one hundred four million, one hundred twenty-three thousand, five hundred thirteen".