411100112024131 has 2 divisors, whose sum is σ = 411100112024132. Its totient is φ = 411100112024130.

The previous prime is 411100112024083. The next prime is 411100112024209. The reversal of 411100112024131 is 131420211001114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 411100112024131 - 2¹³ = 411100112015939 is a prime.

It is a super-2 number, since 2×411100112024131² (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (411100112024831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205550056012065 + 205550056012066.

It is an arithmetic number, because the mean of its divisors is an integer number (205550056012066).

Almost surely, 2^{411100112024131} is an apocalyptic number.

411100112024131 is a deficient number, since it is larger than the sum of its proper divisors (1).

411100112024131 is an equidigital number, since it uses as much as digits as its factorization.

411100112024131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 411100112024131 its reverse (131420211001114), we get a palindrome (542520323025245).

The spelling of 411100112024131 in words is "four hundred eleven trillion, one hundred billion, one hundred twelve million, twenty-four thousand, one hundred thirty-one".