Base | Representation |
---|---|
bin | 100110010010011010… |
… | …011110100011110001 |
3 | 10221010002211021202021 |
4 | 212102122132203301 |
5 | 1133143421320423 |
6 | 30515225551441 |
7 | 2653525520020 |
oct | 462232364361 |
9 | 127102737667 |
10 | 41111120113 |
11 | 16487179028 |
12 | 7b74045581 |
13 | 3b5232789b |
14 | 1dbdda28b7 |
15 | 110931795d |
hex | 99269e8f1 |
41111120113 has 4 divisors (see below), whose sum is σ = 46984137280. Its totient is φ = 35238102948.
The previous prime is 41111120027. The next prime is 41111120119. The reversal of 41111120113 is 31102111114.
41111120113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41111120113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (41111120119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2936508573 + ... + 2936508586.
It is an arithmetic number, because the mean of its divisors is an integer number (11746034320).
Almost surely, 241111120113 is an apocalyptic number.
It is an amenable number.
41111120113 is a deficient number, since it is larger than the sum of its proper divisors (5873017167).
41111120113 is an equidigital number, since it uses as much as digits as its factorization.
41111120113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5873017166.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 41111120113 its reverse (31102111114), we get a palindrome (72213231227).
The spelling of 41111120113 in words is "forty-one billion, one hundred eleven million, one hundred twenty thousand, one hundred thirteen".
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