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41112253413041 is a prime number
BaseRepresentation
bin10010101100100001100010…
…10000101011011010110001
312101120021220121221122201212
421112100301100223122301
520342040343333204131
6223234413011005505
711442155652053366
oct1126206120533261
9171507817848655
1041112253413041
11121106772916a8
12473b9b6599895
1319c2b3ab735a5
14a21bb50c846d
154b46562e8a2b
hex25643142b6b1

41112253413041 has 2 divisors, whose sum is σ = 41112253413042. Its totient is φ = 41112253413040.

The previous prime is 41112253413037. The next prime is 41112253413083. The reversal of 41112253413041 is 14031435221114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32951090012416 + 8161163400625 = 5740304^2 + 2856775^2 .

It is a cyclic number.

It is not a de Polignac number, because 41112253413041 - 22 = 41112253413037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41112253412989 and 41112253413007.

It is not a weakly prime, because it can be changed into another prime (41112253415041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20556126706520 + 20556126706521.

It is an arithmetic number, because the mean of its divisors is an integer number (20556126706521).

Almost surely, 241112253413041 is an apocalyptic number.

It is an amenable number.

41112253413041 is a deficient number, since it is larger than the sum of its proper divisors (1).

41112253413041 is an equidigital number, since it uses as much as digits as its factorization.

41112253413041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 41112253413041 its reverse (14031435221114), we get a palindrome (55143688634155).

The spelling of 41112253413041 in words is "forty-one trillion, one hundred twelve billion, two hundred fifty-three million, four hundred thirteen thousand, forty-one".