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41113100993 is a prime number
BaseRepresentation
bin100110010010100010…
…000010001011000001
310221010020112221000012
4212102202002023001
51133144423212433
630515340234305
72653551410126
oct462242021301
9127106487005
1041113100993
1116488301318
127b7483b995
133b5286c3c3
141dc035a74d
1511095a9848
hex9928822c1

41113100993 has 2 divisors, whose sum is σ = 41113100994. Its totient is φ = 41113100992.

The previous prime is 41113100989. The next prime is 41113101049. The reversal of 41113100993 is 39900131114.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 31029527104 + 10083573889 = 176152^2 + 100417^2 .

It is a cyclic number.

It is not a de Polignac number, because 41113100993 - 22 = 41113100989 is a prime.

It is not a weakly prime, because it can be changed into another prime (41113100933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20556550496 + 20556550497.

It is an arithmetic number, because the mean of its divisors is an integer number (20556550497).

Almost surely, 241113100993 is an apocalyptic number.

It is an amenable number.

41113100993 is a deficient number, since it is larger than the sum of its proper divisors (1).

41113100993 is an equidigital number, since it uses as much as digits as its factorization.

41113100993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 32.

The spelling of 41113100993 in words is "forty-one billion, one hundred thirteen million, one hundred thousand, nine hundred ninety-three".