Base | Representation |
---|---|
bin | 111011110101000000110… |
… | …000001010011111110001 |
3 | 112120001011110010110000121 |
4 | 323311000300022133301 |
5 | 1014330041214220001 |
6 | 12424423133050241 |
7 | 603015403661545 |
oct | 73650060123761 |
9 | 15501143113017 |
10 | 4111370070001 |
11 | 1345693248637 |
12 | 564989626981 |
13 | 23a9150c4c3c |
14 | 102dc4483a25 |
15 | 71e2d4d46a1 |
hex | 3bd40c0a7f1 |
4111370070001 has 2 divisors, whose sum is σ = 4111370070002. Its totient is φ = 4111370070000.
The previous prime is 4111370069993. The next prime is 4111370070013. The reversal of 4111370070001 is 1000700731114.
4111370070001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2646725519376 + 1464644550625 = 1626876^2 + 1210225^2 .
It is a cyclic number.
It is not a de Polignac number, because 4111370070001 - 23 = 4111370069993 is a prime.
It is not a weakly prime, because it can be changed into another prime (4111370070061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055685035000 + 2055685035001.
It is an arithmetic number, because the mean of its divisors is an integer number (2055685035001).
Almost surely, 24111370070001 is an apocalyptic number.
It is an amenable number.
4111370070001 is a deficient number, since it is larger than the sum of its proper divisors (1).
4111370070001 is an equidigital number, since it uses as much as digits as its factorization.
4111370070001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 588, while the sum is 25.
The spelling of 4111370070001 in words is "four trillion, one hundred eleven billion, three hundred seventy million, seventy thousand, one".
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