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4111370070001 is a prime number
BaseRepresentation
bin111011110101000000110…
…000001010011111110001
3112120001011110010110000121
4323311000300022133301
51014330041214220001
612424423133050241
7603015403661545
oct73650060123761
915501143113017
104111370070001
111345693248637
12564989626981
1323a9150c4c3c
14102dc4483a25
1571e2d4d46a1
hex3bd40c0a7f1

4111370070001 has 2 divisors, whose sum is σ = 4111370070002. Its totient is φ = 4111370070000.

The previous prime is 4111370069993. The next prime is 4111370070013. The reversal of 4111370070001 is 1000700731114.

4111370070001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2646725519376 + 1464644550625 = 1626876^2 + 1210225^2 .

It is a cyclic number.

It is not a de Polignac number, because 4111370070001 - 23 = 4111370069993 is a prime.

It is not a weakly prime, because it can be changed into another prime (4111370070061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2055685035000 + 2055685035001.

It is an arithmetic number, because the mean of its divisors is an integer number (2055685035001).

Almost surely, 24111370070001 is an apocalyptic number.

It is an amenable number.

4111370070001 is a deficient number, since it is larger than the sum of its proper divisors (1).

4111370070001 is an equidigital number, since it uses as much as digits as its factorization.

4111370070001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 588, while the sum is 25.

The spelling of 4111370070001 in words is "four trillion, one hundred eleven billion, three hundred seventy million, seventy thousand, one".