Base | Representation |
---|---|
bin | 111011110101000010101… |
… | …110001101010000010011 |
3 | 112120001020202022010100201 |
4 | 323311002232031100103 |
5 | 1014330123144031233 |
6 | 12424430313200031 |
7 | 603016254555355 |
oct | 73650256152023 |
9 | 15501222263321 |
10 | 4111403111443 |
11 | 13456aa966111 |
12 | 564998700017 |
13 | 23a91bbc33a4 |
14 | 102dc8a050d5 |
15 | 71e3135e77d |
hex | 3bd42b8d413 |
4111403111443 has 4 divisors (see below), whose sum is σ = 4111424166240. Its totient is φ = 4111382056648.
The previous prime is 4111403111411. The next prime is 4111403111461. The reversal of 4111403111443 is 3441113041114.
4111403111443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4111403111443 - 25 = 4111403111411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4111403111743) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10231723 + ... + 10625956.
It is an arithmetic number, because the mean of its divisors is an integer number (1027856041560).
Almost surely, 24111403111443 is an apocalyptic number.
4111403111443 is a deficient number, since it is larger than the sum of its proper divisors (21054797).
4111403111443 is a wasteful number, since it uses less digits than its factorization.
4111403111443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21054796.
The product of its (nonzero) digits is 2304, while the sum is 28.
Adding to 4111403111443 its reverse (3441113041114), we get a palindrome (7552516152557).
The spelling of 4111403111443 in words is "four trillion, one hundred eleven billion, four hundred three million, one hundred eleven thousand, four hundred forty-three".
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