Base | Representation |
---|---|
bin | 100110010010101011… |
… | …101100001100010001 |
3 | 10221010102022112110001 |
4 | 212102223230030101 |
5 | 1133201100214101 |
6 | 30515510410001 |
7 | 2653612052254 |
oct | 462253541421 |
9 | 127112275401 |
10 | 41115632401 |
11 | 16489780198 |
12 | 7b75660901 |
13 | 3b5324768c |
14 | 1dc081909b |
15 | 1109909901 |
hex | 992aec311 |
41115632401 has 2 divisors, whose sum is σ = 41115632402. Its totient is φ = 41115632400.
The previous prime is 41115632329. The next prime is 41115632417. The reversal of 41115632401 is 10423651114.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36572737600 + 4542894801 = 191240^2 + 67401^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41115632401 is a prime.
It is a super-2 number, since 2×411156324012 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 41115632401.
It is not a weakly prime, because it can be changed into another prime (41115632431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20557816200 + 20557816201.
It is an arithmetic number, because the mean of its divisors is an integer number (20557816201).
Almost surely, 241115632401 is an apocalyptic number.
It is an amenable number.
41115632401 is a deficient number, since it is larger than the sum of its proper divisors (1).
41115632401 is an equidigital number, since it uses as much as digits as its factorization.
41115632401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 28.
The spelling of 41115632401 in words is "forty-one billion, one hundred fifteen million, six hundred thirty-two thousand, four hundred one".
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