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411204413353 is a prime number
BaseRepresentation
bin1011111101111011011…
…00010110011110101001
31110022101112122112122011
411332331230112132221
523214121312211403
6512523225355521
741465012562106
oct5767554263651
91408345575564
10411204413353
11149433197a48
126783b638ba1
132ca12a06a26
1415c8c283aad
15aa6a3b4a6d
hex5fbdb167a9

411204413353 has 2 divisors, whose sum is σ = 411204413354. Its totient is φ = 411204413352.

The previous prime is 411204413309. The next prime is 411204413357. The reversal of 411204413353 is 353314402114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 229146030864 + 182058382489 = 478692^2 + 426683^2 .

It is a cyclic number.

It is not a de Polignac number, because 411204413353 - 237 = 273765459881 is a prime.

It is not a weakly prime, because it can be changed into another prime (411204413357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205602206676 + 205602206677.

It is an arithmetic number, because the mean of its divisors is an integer number (205602206677).

Almost surely, 2411204413353 is an apocalyptic number.

It is an amenable number.

411204413353 is a deficient number, since it is larger than the sum of its proper divisors (1).

411204413353 is an equidigital number, since it uses as much as digits as its factorization.

411204413353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 411204413353 its reverse (353314402114), we get a palindrome (764518815467).

The spelling of 411204413353 in words is "four hundred eleven billion, two hundred four million, four hundred thirteen thousand, three hundred fifty-three".