Base | Representation |
---|---|
bin | 1011111101111100001… |
… | …01111001111011000011 |
3 | 1110022102000020212122001 |
4 | 11332332011321323003 |
5 | 23214130021042011 |
6 | 512524025124431 |
7 | 41465123532061 |
oct | 5767605717303 |
9 | 1408360225561 |
10 | 411211112131 |
11 | 149436a52926 |
12 | 67841929717 |
13 | 2ca14210ac1 |
14 | 15c8d109031 |
15 | aa6ac897c1 |
hex | 5fbe179ec3 |
411211112131 has 2 divisors, whose sum is σ = 411211112132. Its totient is φ = 411211112130.
The previous prime is 411211112107. The next prime is 411211112173. The reversal of 411211112131 is 131211112114.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 411211112131 - 27 = 411211112003 is a prime.
It is a super-2 number, since 2×4112111121312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 411211112099 and 411211112108.
It is not a weakly prime, because it can be changed into another prime (411211212131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205605556065 + 205605556066.
It is an arithmetic number, because the mean of its divisors is an integer number (205605556066).
Almost surely, 2411211112131 is an apocalyptic number.
411211112131 is a deficient number, since it is larger than the sum of its proper divisors (1).
411211112131 is an equidigital number, since it uses as much as digits as its factorization.
411211112131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48, while the sum is 19.
Adding to 411211112131 its reverse (131211112114), we get a palindrome (542422224245).
The spelling of 411211112131 in words is "four hundred eleven billion, two hundred eleven million, one hundred twelve thousand, one hundred thirty-one".
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