Base | Representation |
---|---|
bin | 10010101100110010011100… |
… | …11011000111100100011010 |
3 | 12101121011100101002100021011 |
4 | 21112121032123013210122 |
5 | 20342212442122424032 |
6 | 223242513542004134 |
7 | 11442626646062215 |
oct | 1126311633074432 |
9 | 171534311070234 |
10 | 41121332623642 |
11 | 12114506264a37 |
12 | 474170b11664a |
13 | 19c3956b6885b |
14 | a223d6c3c77c |
15 | 4b49d8420247 |
hex | 25664e6c791a |
41121332623642 has 16 divisors (see below), whose sum is σ = 62043661345320. Its totient is φ = 20440426528768.
The previous prime is 41121332623627. The next prime is 41121332623673. The reversal of 41121332623642 is 24632623312114.
41121332623642 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 39989447285841 + 1131885337801 = 6323721^2 + 1063901^2 .
It is a junction number, because it is equal to n+sod(n) for n = 41121332623595 and 41121332623604.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78326383 + ... + 78849634.
Almost surely, 241121332623642 is an apocalyptic number.
41121332623642 is a deficient number, since it is larger than the sum of its proper divisors (20922328721678).
41121332623642 is a wasteful number, since it uses less digits than its factorization.
41121332623642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157176785.
The product of its digits is 248832, while the sum is 40.
Adding to 41121332623642 its reverse (24632623312114), we get a palindrome (65753955935756).
The spelling of 41121332623642 in words is "forty-one trillion, one hundred twenty-one billion, three hundred thirty-two million, six hundred twenty-three thousand, six hundred forty-two".
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