411213523403 has 2 divisors, whose sum is σ = 411213523404. Its totient is φ = 411213523402.

The previous prime is 411213523349. The next prime is 411213523451. The reversal of 411213523403 is 304325312114.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 411213523403 - 2¹⁸ = 411213261259 is a prime.

It is not a weakly prime, because it can be changed into another prime (411213523493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 205606761701 + 205606761702.

It is an arithmetic number, because the mean of its divisors is an integer number (205606761702).

Almost surely, 2^411213523403 is an apocalyptic number.

411213523403 is a deficient number, since it is larger than the sum of its proper divisors (1).

411213523403 is an equidigital number, since it uses as much as digits as its factorization.

411213523403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 411213523403 its reverse (304325312114), we get a palindrome (715538835517).

The spelling of 411213523403 in words is "four hundred eleven billion, two hundred thirteen million, five hundred twenty-three thousand, four hundred three".