411221444122113 has 4 divisors (see below), whose sum is σ = 548295258829488. Its totient is φ = 274147629414740.

The previous prime is 411221444122109. The next prime is 411221444122163. The reversal of 411221444122113 is 311221444122114.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 411221444122113 - 2² = 411221444122109 is a prime.

It is a super-2 number, since 2×411221444122113² (a number of 30 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (411221444122163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 68536907353683 + ... + 68536907353688.

It is an arithmetic number, because the mean of its divisors is an integer number (137073814707372).

Almost surely, 2^{411221444122113} is an apocalyptic number.

It is an amenable number.

411221444122113 is a deficient number, since it is larger than the sum of its proper divisors (137073814707375).

411221444122113 is a wasteful number, since it uses less digits than its factorization.

411221444122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 137073814707374.

The product of its digits is 12288, while the sum is 33.

Adding to 411221444122113 its reverse (311221444122114), we get a palindrome (722442888244227).

Subtracting from 411221444122113 its reverse (311221444122114), we obtain a palindrome (99999999999999).

The spelling of 411221444122113 in words is "four hundred eleven trillion, two hundred twenty-one billion, four hundred forty-four million, one hundred twenty-two thousand, one hundred thirteen".