Base | Representation |
---|---|
bin | 111011110101110011011… |
… | …110101011010111110011 |
3 | 112120010100202112110202011 |
4 | 323311303132223113303 |
5 | 1014333312101432313 |
6 | 12425043414103351 |
7 | 603045446553022 |
oct | 73656336532763 |
9 | 15503322473664 |
10 | 4112221124083 |
11 | 1345a8a68a116 |
12 | 564b8664ab57 |
13 | 23aa1c511c37 |
14 | 1030654dc8b9 |
15 | 71e7d09393d |
hex | 3bd737ab5f3 |
4112221124083 has 2 divisors, whose sum is σ = 4112221124084. Its totient is φ = 4112221124082.
The previous prime is 4112221124017. The next prime is 4112221124153. The reversal of 4112221124083 is 3804211222114.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4112221124083 is a prime.
It is not a weakly prime, because it can be changed into another prime (4112221124183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056110562041 + 2056110562042.
It is an arithmetic number, because the mean of its divisors is an integer number (2056110562042).
Almost surely, 24112221124083 is an apocalyptic number.
4112221124083 is a deficient number, since it is larger than the sum of its proper divisors (1).
4112221124083 is an equidigital number, since it uses as much as digits as its factorization.
4112221124083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 4112221124083 its reverse (3804211222114), we get a palindrome (7916432346197).
The spelling of 4112221124083 in words is "four trillion, one hundred twelve billion, two hundred twenty-one million, one hundred twenty-four thousand, eighty-three".
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