Base | Representation |
---|---|
bin | 111011110110100001111… |
… | …101101011000010001011 |
3 | 112120012101010000022220002 |
4 | 323312201331223002023 |
5 | 1014341411224013344 |
6 | 12425253033353215 |
7 | 603103666445654 |
oct | 73664175530213 |
9 | 15505333008802 |
10 | 4113001001099 |
11 | 134634a926281 |
12 | 56516386880b |
13 | 23ab14c6a723 |
14 | 1030dad0a52b |
15 | 71ec679344e |
hex | 3bda1f6b08b |
4113001001099 has 2 divisors, whose sum is σ = 4113001001100. Its totient is φ = 4113001001098.
The previous prime is 4113001001071. The next prime is 4113001001111. The reversal of 4113001001099 is 9901001003114.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4113001001099 - 224 = 4112984223883 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (4113001006099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056500500549 + 2056500500550.
It is an arithmetic number, because the mean of its divisors is an integer number (2056500500550).
Almost surely, 24113001001099 is an apocalyptic number.
4113001001099 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113001001099 is an equidigital number, since it uses as much as digits as its factorization.
4113001001099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 29.
The spelling of 4113001001099 in words is "four trillion, one hundred thirteen billion, one million, one thousand, ninety-nine".
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