Base | Representation |
---|---|
bin | 111011110110100010101… |
… | …101000011000011000111 |
3 | 112120012101222101021201221 |
4 | 323312202231003003013 |
5 | 1014341422413421411 |
6 | 12425254155501211 |
7 | 603104210142232 |
oct | 73664255030307 |
9 | 15505358337657 |
10 | 4113013420231 |
11 | 1346356938a21 |
12 | 565167a57807 |
13 | 23ab176c8421 |
14 | 1030dc820419 |
15 | 71ec78e8071 |
hex | 3bda2b430c7 |
4113013420231 has 16 divisors (see below), whose sum is σ = 4187824044768. Its totient is φ = 4038828393600.
The previous prime is 4113013420223. The next prime is 4113013420297. The reversal of 4113013420231 is 1320243103114.
It is a cyclic number.
It is not a de Polignac number, because 4113013420231 - 23 = 4113013420223 is a prime.
It is a super-2 number, since 2×41130134202312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 4113013420196 and 4113013420205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113013420331) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28125241 + ... + 28271101.
It is an arithmetic number, because the mean of its divisors is an integer number (261739002798).
Almost surely, 24113013420231 is an apocalyptic number.
4113013420231 is a deficient number, since it is larger than the sum of its proper divisors (74810624537).
4113013420231 is a wasteful number, since it uses less digits than its factorization.
4113013420231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 148002.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4113013420231 its reverse (1320243103114), we get a palindrome (5433256523345).
The spelling of 4113013420231 in words is "four trillion, one hundred thirteen billion, thirteen million, four hundred twenty thousand, two hundred thirty-one".
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