Base | Representation |
---|---|
bin | 111011110110101000000… |
… | …100110011000100110110 |
3 | 112120012122020221110022112 |
4 | 323312220010303010312 |
5 | 1014342114001013332 |
6 | 12425311135131022 |
7 | 603106353112610 |
oct | 73665004630466 |
9 | 15505566843275 |
10 | 4113103532342 |
11 | 13463a2796542 |
12 | 565192073a72 |
13 | 23ab302893bc |
14 | 10310a799db0 |
15 | 71ed0797db2 |
hex | 3bda8133136 |
4113103532342 has 16 divisors (see below), whose sum is σ = 7051063300512. Its totient is φ = 1762751488320.
The previous prime is 4113103532341. The next prime is 4113103532393. The reversal of 4113103532342 is 2432353013114.
4113103532342 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 4113103532299 and 4113103532308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4113103532341) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4423418 + ... + 5271890.
It is an arithmetic number, because the mean of its divisors is an integer number (440691456282).
Almost surely, 24113103532342 is an apocalyptic number.
4113103532342 is a deficient number, since it is larger than the sum of its proper divisors (2937959768170).
4113103532342 is a wasteful number, since it uses less digits than its factorization.
4113103532342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1194743.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 4113103532342 its reverse (2432353013114), we get a palindrome (6545456545456).
The spelling of 4113103532342 in words is "four trillion, one hundred thirteen billion, one hundred three million, five hundred thirty-two thousand, three hundred forty-two".
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