411313131331 has 4 divisors (see below), whose sum is σ = 413019825064. Its totient is φ = 409606437600.

The previous prime is 411313131311. The next prime is 411313131367. The reversal of 411313131331 is 133131313114.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 411313131331 - 2⁹ = 411313130819 is a prime.

It is a super-2 number, since 2×411313131331² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 411313131296 and 411313131305.

It is not an unprimeable number, because it can be changed into a prime (411313131301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 853346505 + ... + 853346986.

It is an arithmetic number, because the mean of its divisors is an integer number (103254956266).

Almost surely, 2^411313131331 is an apocalyptic number.

411313131331 is a deficient number, since it is larger than the sum of its proper divisors (1706693733).

411313131331 is a wasteful number, since it uses less digits than its factorization.

411313131331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1706693732.

The product of its digits is 972, while the sum is 25.

Adding to 411313131331 its reverse (133131313114), we get a palindrome (544444444445).

The spelling of 411313131331 in words is "four hundred eleven billion, three hundred thirteen million, one hundred thirty-one thousand, three hundred thirty-one".