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4113140032283 is a prime number
BaseRepresentation
bin111011110110101010010…
…000000010001100011011
3112120012201210121211211012
4323312222100002030123
51014342202322013113
612425314521324135
7603110305262462
oct73665220021433
915505653554735
104113140032283
111346411356487
125651a233664b
1323ab379c8ab9
1410311157b9d9
1571ed3aa7aa8
hex3bdaa40231b

4113140032283 has 2 divisors, whose sum is σ = 4113140032284. Its totient is φ = 4113140032282.

The previous prime is 4113140032279. The next prime is 4113140032367. The reversal of 4113140032283 is 3822300413114.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4113140032283 - 22 = 4113140032279 is a prime.

It is a super-3 number, since 3×41131400322833 (a number of 39 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (4113140032483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056570016141 + 2056570016142.

It is an arithmetic number, because the mean of its divisors is an integer number (2056570016142).

Almost surely, 24113140032283 is an apocalyptic number.

4113140032283 is a deficient number, since it is larger than the sum of its proper divisors (1).

4113140032283 is an equidigital number, since it uses as much as digits as its factorization.

4113140032283 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 4113140032283 its reverse (3822300413114), we get a palindrome (7935440445397).

The spelling of 4113140032283 in words is "four trillion, one hundred thirteen billion, one hundred forty million, thirty-two thousand, two hundred eighty-three".