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4113301322001 = 310717112793577
BaseRepresentation
bin111011110110110011110…
…111010011100100010001
3112120020011001010012201110
4323312303313103210101
51014343020114301001
612425342522323533
7603114304233054
oct73666367234421
915506131105643
104113301322001
1113464943a9873
125652283595a9
1323ab6224b5c1
14103128b64a9b
1571ee2d173d6
hex3bdb3dd3911

4113301322001 has 8 divisors (see below), whose sum is σ = 5484453365664. Its totient is φ = 2742175079840.

The previous prime is 4113301321957. The next prime is 4113301322041. The reversal of 4113301322001 is 1002231033114.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4113301322001 - 227 = 4113167104273 is a prime.

It is not an unprimeable number, because it can be changed into a prime (4113301322041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6075276 + ... + 6718301.

It is an arithmetic number, because the mean of its divisors is an integer number (685556670708).

Almost surely, 24113301322001 is an apocalyptic number.

It is an amenable number.

4113301322001 is a deficient number, since it is larger than the sum of its proper divisors (1371152043663).

4113301322001 is a wasteful number, since it uses less digits than its factorization.

4113301322001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12900751.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 4113301322001 its reverse (1002231033114), we get a palindrome (5115532355115).

The spelling of 4113301322001 in words is "four trillion, one hundred thirteen billion, three hundred one million, three hundred twenty-two thousand, one".

Divisors: 1 3 107171 321513 12793577 38380731 1371100440667 4113301322001