Base | Representation |
---|---|
bin | 111011110110110011111… |
… | …010010010100000111011 |
3 | 112120020011002120221120221 |
4 | 323312303322102200323 |
5 | 1014343020314312443 |
6 | 12425342551200511 |
7 | 603114314001232 |
oct | 73666372224073 |
9 | 15506132527527 |
10 | 4113302104123 |
11 | 1346494893453 |
12 | 565228676137 |
13 | 23ab624635b4 |
14 | 103128cc9b19 |
15 | 71ee2e1deed |
hex | 3bdb3e9283b |
4113302104123 has 4 divisors (see below), whose sum is σ = 4113308595960. Its totient is φ = 4113295612288.
The previous prime is 4113302104099. The next prime is 4113302104147. The reversal of 4113302104123 is 3214012033114.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (4113302104099) and next prime (4113302104147).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4113302104123 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (4113302105123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2178493 + ... + 3601726.
It is an arithmetic number, because the mean of its divisors is an integer number (1028327148990).
Almost surely, 24113302104123 is an apocalyptic number.
4113302104123 is a deficient number, since it is larger than the sum of its proper divisors (6491837).
4113302104123 is an equidigital number, since it uses as much as digits as its factorization.
4113302104123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6491836.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 4113302104123 its reverse (3214012033114), we get a palindrome (7327314137237).
The spelling of 4113302104123 in words is "four trillion, one hundred thirteen billion, three hundred two million, one hundred four thousand, one hundred twenty-three".
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