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41133044314129 is a prime number
BaseRepresentation
bin10010101101001000010000…
…11111101011000000010001
312101122021120120200212022111
421112210020133223000101
520342410433321023004
6223252132032105321
711443523116566355
oct1126441037530021
9171567516625274
1041133044314129
11121194761a7389
124743a39395241
1319c4aa2366721
14a22bc844b465
154b4e716e0a04
hex2569087eb011

41133044314129 has 2 divisors, whose sum is σ = 41133044314130. Its totient is φ = 41133044314128.

The previous prime is 41133044314079. The next prime is 41133044314133. The reversal of 41133044314129 is 92141344033114.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40965376176400 + 167668137729 = 6400420^2 + 409473^2 .

It is a cyclic number.

It is not a de Polignac number, because 41133044314129 - 225 = 41133010759697 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41133044314091 and 41133044314100.

It is not a weakly prime, because it can be changed into another prime (41133054314129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20566522157064 + 20566522157065.

It is an arithmetic number, because the mean of its divisors is an integer number (20566522157065).

Almost surely, 241133044314129 is an apocalyptic number.

It is an amenable number.

41133044314129 is a deficient number, since it is larger than the sum of its proper divisors (1).

41133044314129 is an equidigital number, since it uses as much as digits as its factorization.

41133044314129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 40.

The spelling of 41133044314129 in words is "forty-one trillion, one hundred thirty-three billion, forty-four million, three hundred fourteen thousand, one hundred twenty-nine".