Base | Representation |
---|---|
bin | 111011110110110101101… |
… | …001000011101011010011 |
3 | 112120020020010020012011002 |
4 | 323312311221003223103 |
5 | 1014343100233010311 |
6 | 12425345505412215 |
7 | 603115115546636 |
oct | 73666551035323 |
9 | 15506203205132 |
10 | 4113331141331 |
11 | 13464aa216545 |
12 | 56523633a06b |
13 | 23ab6848c289 |
14 | 10312cac7c1d |
15 | 71ee575793b |
hex | 3bdb5a43ad3 |
4113331141331 has 2 divisors, whose sum is σ = 4113331141332. Its totient is φ = 4113331141330.
The previous prime is 4113331141301. The next prime is 4113331141343. The reversal of 4113331141331 is 1331411333114.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4113331141331 is a prime.
It is a super-3 number, since 3×41133311413313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 4113331141294 and 4113331141303.
It is not a weakly prime, because it can be changed into another prime (4113331141301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2056665570665 + 2056665570666.
It is an arithmetic number, because the mean of its divisors is an integer number (2056665570666).
Almost surely, 24113331141331 is an apocalyptic number.
4113331141331 is a deficient number, since it is larger than the sum of its proper divisors (1).
4113331141331 is an equidigital number, since it uses as much as digits as its factorization.
4113331141331 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3888, while the sum is 29.
Adding to 4113331141331 its reverse (1331411333114), we get a palindrome (5444742474445).
The spelling of 4113331141331 in words is "four trillion, one hundred thirteen billion, three hundred thirty-one million, one hundred forty-one thousand, three hundred thirty-one".
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